Can you make a working simulatin on how a prosessor ram and memory works please draw a prosessor with its parths to the ram and memory batter , and a screean with osalating lines showing the electrin pathes's game

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No:51645

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Can you make a working simulatin on how a prosesso..ALL
Developer User18896｜Date and time 24/3/14 10:09:33
Build time 1.791 sec｜Game capacity 0.277KB｜

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[PR]現在のフィギュア売れ筋ランキング

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<p style='font-size:14px;background-color:#FF0'>The AI could not be gamified with this prompt. Please try again with different prompts. . <br>Displays games created by AI in the past at random.</p><!DOCTYPE html>
<html>
<head>
	<title>流れ星</title>
	<meta charset="UTF-8">
	<style>
		body {
			margin: 0;
			padding: 0;
			background: black;
		}
		canvas {
			display: block;
			position: absolute;
			top: 0;
			left: 0;
			width: 100%;
			height: 100%;
		}
	</style>
</head>
<body>
	<canvas id="canvas"></canvas>
	<script>
		var canvas = document.getElementById("canvas");
		var ctx = canvas.getContext("2d");

canvas.width = window.innerWidth;
		canvas.height = window.innerHeight;
		window.addEventListener("resize", function() {
			canvas.width = window.innerWidth;
			canvas.height = window.innerHeight;
		});

canvas.addEventListener("click", function(event) {
			var x = event.clientX;
			var y = event.clientY;
			var size = Math.floor(Math.random() * 30) + 10;
			var color = "hsl(" + Math.floor(Math.random() * 360) + ", 100%, 50%)";

drawStar(x, y, size, color);
		});

function drawStar(x, y, size, color) {
			ctx.beginPath();
			ctx.strokeStyle = color;
			ctx.lineWidth = size / 10;
			ctx.lineCap = "round";
			ctx.moveTo(x, y);
			var length = size * (2 + Math.random() * 2);
			var angle = Math.PI / 4 + Math.random() * Math.PI / 4;
			var endX = x + length * Math.cos(angle);
			var endY = y + length * Math.sin(angle);
			ctx.lineTo(endX, endY);
			ctx.stroke();

for (var i = 0; i < 5 + Math.floor(Math.random() * 10); i++) {
				var starSize = Math.random() * 3;
				ctx.fillStyle = "white";
				ctx.fillRect(endX - starSize / 2, endY - starSize / 2, starSize, starSize);
			}
		}
	</script>
</body>
</html>